Bituminous Layers Machinery Fuel & Cost Calculation Step-by-Step

Bituminous layers Fuel, Oil & Lubricant Consumption Calculator

Bituminous Layers Fuel, Oil & Lubricant Calculation (Step-by-Step Solved Example)

Sample Inputs (Default Values):
  • BC/DBM/OGC Quantity ($V$): $100\text{ m}^3$
  • Thickness of BC Layer ($t$): $50\text{ mm} = 0.05\text{ m}$
  • Road Width ($W$): $3.75\text{ m}$
  • Distance to Site ($d$): $10\text{ km}$
  • Truck Mileage: $3\text{ km/L}$
  • Roller Width ($W_r$): $2.0\text{ m}$
  • Paver Effective Width ($W_p$): $2.5\text{ m}$
  • Unit Rates: Fuel = ₹$110\text{/L}$, Engine Oil = ₹$200\text{/L}$, Lubricant = ₹$400\text{/L}$

Step 1: Calculate Road Paving Length ($L$)

Using the geometric relationship $V = L \times W \times t$:

$$L = \frac{V}{W \times t}$$ $$L = \frac{100}{3.75 \times 0.05} = \frac{100}{0.1875} = \mathbf{533.33\text{ m}}$$

Step 2: Machinery Operations & Running Time

  1. Roller Calculations:
    • Roller Passes $= \max\left(4, \text{round}\left(6 \times \frac{t_{mm}}{50}\right)\right) = \max\left(4, \text{round}\left(6 \times \frac{50}{50}\right)\right) = \mathbf{6\text{ passes}}$
    • Roller Strips $= \frac{W}{W_r} = \frac{3.75}{2.0} = \mathbf{1.875\text{ strips}}$
    • Roller Distance $= \text{Passes} \times L \times \text{Strips} = 6 \times 533.333 \times 1.875 = \mathbf{6000.00\text{ m}}$
    • Roller Time ($T_r$) at $2\text{ km/h}$ ($2000\text{ m/h}$): $$T_r = \frac{6000}{2000} = \mathbf{3.00\text{ hours}}$$
  2. Truck Calculations:
    • Capacity per trip $= 10\text{ m}^3$
    • Truck Trips $= \lceil \frac{V}{\text{Capacity}} \rceil = \lceil \frac{100}{10} \rceil = \mathbf{10\text{ trips}}$
    • Total Distance $= \text{Trips} \times d \times 2 = 10 \times 10 \times 2 = \mathbf{200.00\text{ km}}$
    • Truck Time ($T_t$) at assumed $40\text{ km/h}$: $$T_t = \frac{200}{40} = \mathbf{5.00\text{ hours}}$$
  3. Paver Calculations:
    • Paver Lanes $= \frac{W}{W_p} = \frac{3.75}{2.5} = \mathbf{1.50\text{ lanes}}$
    • Paver Travel Distance $= \text{Lanes} \times L = 1.50 \times 533.333 = \mathbf{800.00\text{ m}}$
    • Paver Time ($T_p$) at speed of $2\text{ m/min}$ ($120\text{ m/h}$): $$T_p = \frac{800}{120} = \mathbf{6.67\text{ hours}}$$

Step 3: Calculate Fuel, Oil & Lubricant Consumption

  1. Fuel Consumption:
    • Roller (at $0.5\text{ L/km}$): $\frac{6000\text{ m}}{1000} \times 0.5 = \mathbf{3.00\text{ L}}$
    • Truck (at $3\text{ km/L}$): $\frac{200\text{ km}}{3} = \mathbf{66.67\text{ L}}$
    • Paver (at $4\text{ L/hr}$): $6.667\text{ hrs} \times 4 = \mathbf{26.67\text{ L}}$
    • Total Fuel: $3.00 + 66.67 + 26.67 = \mathbf{96.33\text{ L}}$
  2. Engine Oil Consumption (at norm $0.04\text{ L/hr}$):
    • Roller: $3.00 \times 0.04 = \mathbf{0.12\text{ L}}$
    • Truck: $5.00 \times 0.04 = \mathbf{0.20\text{ L}}$
    • Paver: $6.667 \times 0.04 = \mathbf{0.27\text{ L}}$
    • Total Engine Oil: $0.12 + 0.20 + 0.27 = \mathbf{0.59\text{ L}}$
  3. Lubricant Consumption (at norm $0.01\text{ L/hr}$):
    • Roller: $3.00 \times 0.01 = \mathbf{0.03\text{ L}}$
    • Truck: $5.00 \times 0.01 = \mathbf{0.05\text{ L}}$
    • Paver: $6.667 \times 0.01 = \mathbf{0.07\text{ L}}$
    • Total Lubricant: $0.03 + 0.05 + 0.07 = \mathbf{0.15\text{ L}}$

Step 4: Total Cost & Unit Rate Calculations

  • Fuel Cost: $96.333\text{ L} \times ₹110 = \mathbf{₹10,596.67}$
  • Engine Oil Cost: $0.587\text{ L} \times ₹200 = \mathbf{₹117.33}$
  • Lubricant Cost: $0.147\text{ L} \times ₹400 = \mathbf{₹58.67}$
  • Total Combined Cost: $$\text{Total Cost} = 10596.67 + 117.33 + 58.67 = \mathbf{₹10,772.67}$$
  • Unit Cost per m³ of BC Work: $$\text{Unit Cost} = \frac{₹10772.67}{100\text{ m}^3} = \mathbf{₹107.73\text{ per m}^3}$$

Final Calculation Summary

Machinery Distance / Time Fuel (L) Engine Oil (L) Lubricant (L)
Roller 6,000.00 m (3.00 hrs) 3.00 0.12 0.03
Truck 200.00 km (5.00 hrs) 66.67 0.20 0.05
Paver 800.00 m (6.67 hrs) 26.67 0.27 0.07
Total Consumables - 96.33 L 0.59 L 0.15 L
Total Cost (₹) ₹10,772.67
Cost per m³ of BC ₹107.73 / m³