Shear Lug Design Calculator
Indian Standards (IS 456, IS 800, IS 1893-Part 4) – 2025 Practice
Input Parameters
| Normal Compression Force (N) | kN |
| Shear Force X-direction (Vux) | kN |
| Shear Force Y-direction (Vuy) | kN |
| Concrete Grade (fck) | MPa |
| Steel Yield Strength (Shear Lug) fy | MPa |
| Base Plate Size (A × B) | × mm |
| Grout Thickness (g) | mm |
| Shear Lug Height (hsl) | mm |
| Shear Lug Width (bf) | mm |
| Shear Lug Web Thickness (tw) | mm |
| Shear Lug Flange Thickness (tf) | mm |
| Section Modulus Sx | mm³ |
| Section Modulus Sy | mm³ |
| Anchor Bolt Diameter | mm |
| No. of Anchor Bolts |
Theoretical Background & Design Methodology
This calculator evaluates the adequacy of a shear lug for transferring horizontal shear forces from a steel column base plate to the concrete foundation as per Indian Standards.
Key Design Steps (as implemented in the tool)
1. Friction Resistance:
\( V_{\text{friction}} = \mu \times N \) where \(\mu = 0.40\)
\( V_{\text{friction}} = \mu \times N \) where \(\mu = 0.40\)
2. Net Shear on Lug:
\( V_{\text{net-x}} = \max(0, V_{ux} - V_{\text{friction}}) \)
\( V_{\text{net-y}} = \max(0, V_{uy} - V_{\text{friction}}) \)
\( V_{\text{net-x}} = \max(0, V_{ux} - V_{\text{friction}}) \)
\( V_{\text{net-y}} = \max(0, V_{uy} - V_{\text{friction}}) \)
3. Concrete Bearing Capacity:
Permissible bearing stress = \( 0.6 f_{ck} \)
Effective area = \( b_f \times h_{sl} \)
\( V_{\text{bearing}} = 0.6 f_{ck} \times A_{ef} / 1000 \)
Permissible bearing stress = \( 0.6 f_{ck} \)
Effective area = \( b_f \times h_{sl} \)
\( V_{\text{bearing}} = 0.6 f_{ck} \times A_{ef} / 1000 \)
4. Shear Capacity of Lug Web (IS 800 WSM):
\( \tau_v = 0.4 f_y \)
\( V_{\text{shear,web}} = 0.4 f_y \times (h_{sl} \times t_w) / 1000 \)
\( \tau_v = 0.4 f_y \)
\( V_{\text{shear,web}} = 0.4 f_y \times (h_{sl} \times t_w) / 1000 \)
5. Bending Check:
Eccentricity \( e = 0.5 h_{sl} + g \)
\( M_u = V_u \times e \times 10^{-6} \) kN·m
Allowable bending stress = \( 0.66 f_y \)
Eccentricity \( e = 0.5 h_{sl} + g \)
\( M_u = V_u \times e \times 10^{-6} \) kN·m
Allowable bending stress = \( 0.66 f_y \)
Important Notes from Indian Practice
- Friction coefficient 0.40 is commonly used for grouted base plates.
- Bearing area is taken conservatively without dispersion.
- Working Stress Method (WSM) is used for steel lug design.
- Provide full penetration welds between lug and base plate.
- Confinement reinforcement (ties) around the lug pocket is recommended.
Disclaimer: This tool is for preliminary design and learning purposes. Final design must be reviewed and certified by a qualified structural engineer as per latest Indian Standards.
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